Ashebir shewangizaw
Activities
Ashebir agreed to this Miscellaneous on Apr 30
192.168.187.233 /27...........( based on IP, it lies in 3rd octet...... so that BLOCK SIZE=32 )
here, C.I.D.R= /27.................... its shows that network portion is 27 (it means it lies in 4th octet )
so, we need to do modification in 4th octet , as per the given IP, 4th octet value is 233..
now, we need to divide the 233 by block size (32) and just consider only quotient and leave remain... (more)
- Answer
- Total 2 answers
- 5193
Ashebir asked this Miscellaneous on Apr 17
192.168.187.233 /27...........( based on IP, it lies in 3rd octet...... so that BLOCK SIZE=32 )
here, C.I.D.R= /27.................... its shows that network portion is 27 (it means it lies in 4th octet )
so, we need to do modification in 4th octet , as per the given IP, 4th octet value is 233..
now, we need to divide the 233 by block size (32) and just consider only quotient and leave remain... (more)
- Answer
- Total 2 answers
- 5193